Scherrer’s Example
Ø
Ø
Ø
Ø
t
= 0.89*
λ
/ (
B
Cos
θ
B
)
λ
= 1.54 Ǻ
Ø
= 0.89*
1.54
Ǻ / ( 0.00174 * Cos (98.25/ 2 ) )
Ø
= 1200 Ǻ
Ø
Ø
B
= (98.3 - 98.2)*
π
/180 = 0.00174
Ø
Ø
Simple Right!