Thevenin and Norton Equivalent Circuits:
The Simplest Picture of a Black Box Source
You
are given a power supply in a black box with two terminals. There are two basic measurements you can
make.
(Actually you can get voltages and
currents that exceed these values, but this can only happen if a power source
is placed across its terminals.)
If
you continued your measurements by placing different resistors between the
terminals and then for each resistor, measured the current delivered by the
supply and the voltage across the terminals and graphed your results, you would
get a surprisingly simple answer.

This
simple behavior suggests that whatever is inside the black box can be replaced
with a simple model. This is in fact the
case. It turns out that there are two
simple and equivalent models to describe a black box source. The Thevenin model: an ideal voltage source VTH in
series with a resistor RS.
The Norton model: an ideal current source IN in parallel with a resistor RN.
The
following relationships for any two terminal network
also apply:
RS = RTH = RN VTH = IN
RS IN
= VTH/RS
Note
that the maximum power available from a network is transferred to a resistor
loading that network when the load resistor is equal to RS.
Thevenin's Theorem: Any
two terminals of a network of any number of resistors, current sources and/or
voltage sources can be reduced to one voltage source in series with one
resistor. The voltage that appears across these two terminals is the Thevenin voltage. The Thevenin
equivalent resistance is the resistance between these two terminals with all
sources disabled (replaced by their equivalent resistances), as is done when
applying superposition.

Procedure
to find the Thevenin equivalent circuit.
Observations
of the Thevenin equivalent circuit.
The output voltage is
; Note that when
; ![]()
The short circuit current is (
); ![]()
A plot of iout vs Vout is a straight
line with a slope of −1/RS and a y intercept of iN.
![]()
This is exactly the behavior we found from the general black box power supply!
Norton's Theorem: Any
two terminals of a network of any number of resistors, current sources and/or
voltage sources can be reduced to one current source in parallel with one
resistor. The short-circuit current available from these two terminals
is the Norton current. The Norton equivalent resistance is the resistance
between these two terminals with all sources disabled (replaced by their
equivalent resistances) as is done when applying superposition.

Procedure
to find the Norton equivalent circuit.
Observations
of the Norton equivalent circuit.
The output voltage is
; Note that when
; ![]()
The short circuit current is (
); ![]()
A plot of iout vs Vout is a straight
line with a slope of −1/RS and a y intercept of iN.
![]()
This is exactly the behavior we found from the general black box power supply!
Thevenin-Norton Source Transformation.
These quantities obey the Ohm’s Law relationship:
. Thus if any two
quantities are know the third can be determined.
Example: You have already determined the Thevenin equivalent circuit, you know VTH and RS. The Norton equivalent circuit has the same RS
and the Norton current is
.
Example: You have determined both the open circuit
voltage VTH and the short circuit current IN. The source resistance (for both Thevenin and Norton) is ![]()
Example: Find the Thevenin
equivalent of a voltage divider.
So far we have looked at
circuits which have a voltage or current source explicitly included. The voltage divider is an
example of a circuit were the voltage source is implied and not drawn in
the schematic. The circuit on the left
is the standard way to represent the voltage divider. The schematic on the right is what is
implied.

The output of the voltage divider is always measured with zero current flowing through Vout. That is, Vout is the open circuit voltage which is VTH.

The
source resistance RS is
then the equivalent resistance REQ
seen across the output terminals with the voltage source turned off. The output terminal labeled Vout
is obvious; the second terminal is the point where Vout is
referenced. Here the second terminal is
ground.

In this example R1 and R2 are then in parallel.
![]()
The Norton equivalent current is then:

We could also find the Norton equivalent current by calculating the short circuit current of the voltage divider. The short circuit current is obtained by shorting the output of the voltage divider (left).

Notice that this effectively
removes R2 from the circuit. The short circuit current is then obtained
using Ohm’s law, which is the same result we obtained above.
![]()
We can now find VTH from IN:

Example: Find the Thevenin equivalent of a voltage divider with a series
resistor.
In this example the open circuit voltage is the same as the simple voltage divider because no current is flowing through R3. The source resistance RS is affected by R3 (right).

